If it's not what You are looking for type in the equation solver your own equation and let us solve it.
.3x^2-3.6x+6=0
a = .3; b = -3.6; c = +6;
Δ = b2-4ac
Δ = -3.62-4·.3·6
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.6)-\sqrt{5.76}}{2*.3}=\frac{3.6-\sqrt{5.76}}{0.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.6)+\sqrt{5.76}}{2*.3}=\frac{3.6+\sqrt{5.76}}{0.6} $
| (X-5)+(x-4)+5=26+(x-10) | | 1.85=x/2 | | 1/2n-1/8=3/4+5/6n | | y/8=3/13 | | 4+2r=2r+2 | | -11+5z=18z-13z | | 2x-2=8x-12 | | 4(1y+1)=-8 | | 25p-16p^2=0 | | 8x-(2x-8)=5+5x | | 2x²=x3 | | 7+2(x-1)=7-8(x-8) | | -118=2-8(1+2p) | | 1.85=x/6 | | -.3x^2-3.6-6=0 | | 6x+180-12x=180 | | 1/6g+1/4=1/3+3/4g | | -11+5z=18z | | 5(-2a-4)+10a=-20 | | (14x+3)+(4x10)=157 | | 10x^2-9×-9=0 | | x-12+(-6x)x=-8 | | 3(v-4)-5=-2 | | 2x2=x3 | | 0.4=x/12 | | 140=0.1b | | 15z+20=13z-20 | | 5(5x+1)=25x-7 | | 3-6a=6a | | -18-6x=6(1+3x | | Y=|x+2|-1 | | -3(3+3m)-8=-17+6m |